4v^2+4v+1=0

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Solution for 4v^2+4v+1=0 equation:


Simplifying
4v2 + 4v + 1 = 0

Reorder the terms:
1 + 4v + 4v2 = 0

Solving
1 + 4v + 4v2 = 0

Solving for variable 'v'.

Factor a trinomial.
(1 + 2v)(1 + 2v) = 0

Subproblem 1

Set the factor '(1 + 2v)' equal to zero and attempt to solve: Simplifying 1 + 2v = 0 Solving 1 + 2v = 0 Move all terms containing v to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 2v = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 2v = 0 + -1 2v = 0 + -1 Combine like terms: 0 + -1 = -1 2v = -1 Divide each side by '2'. v = -0.5 Simplifying v = -0.5

Subproblem 2

Set the factor '(1 + 2v)' equal to zero and attempt to solve: Simplifying 1 + 2v = 0 Solving 1 + 2v = 0 Move all terms containing v to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 2v = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 2v = 0 + -1 2v = 0 + -1 Combine like terms: 0 + -1 = -1 2v = -1 Divide each side by '2'. v = -0.5 Simplifying v = -0.5

Solution

v = {-0.5, -0.5}

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